Question

a body of volume 100cm^3 weighs 1kgf in air. find: (1)it's weight in water and (2)it's relative density.

Answer 1

Relative density (σ) = Density of body / Density of water
= (Mass of body / Volume of body) / Density of water
= [1000 g / (100 cm³)] / 1 g/cm³
= 10

Weight in water = Weight in air [1 - 1/σ]
= 1 kg × 9.8 m/s² [1 - 1/10]
= 8.82 N
= 0.9 kgf

Answers:
[1] 0.9 kgf = 8.82 N (or) 90 N if g = 10 m/s²
[2] 10

Answer 2

Answers:

[1] 0.9 kgf = 8.82 N (or) 90 N if g = 10 m/s²

[2] 10

Explanation:

Newton Relative density (σ) = Density of body / Density of water

= (Mass of body / Volume of body) / Density of water

= [1000 g / (100 cm³)] / 1 g/cm³

= 10

Weight in water = Weight in air [1 - 1/σ]

= 1 kg × 9.8 m/s² [1 - 1/10]

= 8.82 N

= 0.9 kgf