A body of volume 100cm3 weighs 5kgf in air.It is completely immersed in a liquid of density 1.8×10^3 kg m^-3 FIND (i) the upthrust due to liquid and (ii) the weight of the body in liquid.
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Given :weight of the body in air=W=5kgf
Volume of Body=V=100³cm=100x10⁻⁶=10⁻⁴m³
Density of liquid=d=1.8x 10³kg/m³
1]The upthrust due to liquid
Upthrust= Buoyant Force B=Vdg
=10⁻⁴x1.8x10³xg
=0.18gN
=0.18kgf
2]The weight of the body in liquid:So weight of Body in Liquid=W-B
=5kgf-0.18kgf
=4.82kgf
Explanation:
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