A body of weight 200N is placed on rough horizontal plane. If the coefficient of friction between the body and the horizontal plane is 0.3, determine the horizontal force required to just slide the body on the plane.
Answers
Answer:
60N
Explanation:
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Given: A body of weight 200N is placed on rough horizontal plane. The coefficient of friction between the body and the horizontal plane is 0.3.
To find: Horizontal force required to just slide the body on the plane
Explanation: Weight of the body= 200 N
On a horizontal plane, the normal reaction on the ground is equal to the weight of the body.
Normal force (N) = 200 N
Frictional force is the force that opposes the relative motion of the body. It is the product of the coefficient of friction and the normal force.
Frictional force
= - Weight* Coefficient of friction
= - 200* 0.3
= -60 N
The force required to just move the body is opposite and equal to the frictional force so that it cancels friction.
Force required= -(-60) N
= 60 N
Therefore, force required to just slide the body is option (a) 60 N.