A body of weight 200N moves in a horizontal circular path of radius 10m with speed of 10ms^-1. What is the centripetal force acting on the body? (g=10ms^-2).
Answers
Answered by
12
- Weight of body (W) = 200N.
- Radius of circular path (r) = 10 m.
- Speed of the body (v) = 10 m/s.
- Acceleration due to gravity (g) = 10 m/s².
Firstly Finding The Mass of the body.
Therefore,
Substituting the values,
It becomes,
So, the mass of the body is 20Kg.
Now, From Expression Of Centripetal Force.
Substituting the values,
So, The Centripetal Force acting on the body is 200N.
Some Important formulas:-
- Tangential acceleration =
- Centripetal acceleration =
- Relation b/w Angular velocity and Linear velocity v = rω.
αmαn4чσu:
great answer bhaiya
Answered by
11
Given :-
Weight of body (W) = 200 N
Radius of path = 10 m
Speed (v) = 10 m/s
Take g as 10 m/s²
=======================================
To Find :-
Centripetal force acting on body
=========================================
Solution :-
As, we know that
____________[Put Values]
For Calculating value of Centripital force we have formula :-
Where,
Fc is centripital force
r is radius
m is mass
v is velocity
____________[Put Values]
∴ Centripital force is 200 N
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