A body of weight 280 N is placed on an inclined plane as shown in figure. The components of weight parallel to plane and normal to plane are
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Answer:
The component of weight parallel to plane =140
The component of weight Normal to plane=140√3
Step-by-step explanation:
- Here mg is taken as weight,angle is 30° given and its component is calculated.
( diagram is attached below)
- component of weight parallel to the plane is=mgsinθ
=280×Sin(30°)
=280× 1/2
=140
- component of weight normal to the plane =280cosθ
=280×cos(30°)
=280×√3/2
=140√3
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