A body of weight 50 n placed on horizontal surface is just moved by a force of 28.2n. and angle of elevation is 45 degree. determine frictional force and normal reaction
Answers
Answered by
11
Normal reaction force for a body on an inclined plane is :
N = mgCosФ
N = mg Cos 45
Mg = 50
Cos 45 = 0.7071
N = 0.7071 × 50 = 35.36N
The resultant force responsible for the motion is :
F = f + mg Sin Ф
f = the frictional force.
mg Sin 45 = 50 × 0.7071 = 35.36 N
28.2 N is the resultant force.
28.2 = 35.36 + f
f = 28.2 - 35.36 = - 7.4 N
We take the absolute value = 7.4 N
Similar questions