Question

A body of weight 50kg descending in a lift with downward accelation 9.8 m/sec2. the apparent weight of the boy is

Answer 1

Heya.........!!!!

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This is a question on ' Motion of a Body in a Lift '

If the lift is at rest then his weight = Mg

But according to the question the lift is going downwards with an acceleration ( a ) of 9.8 m/s^2 .

As the lift is going down so the apparent weight of the body will be :-

=> W = M( g - a )

here • W = his apparent weight .
• a = acceleration of lift .
• g = acceleration due to gravity = 9.8 m/s^2

substituting the values we'll get -

=> W = 50 ( 9.8 - 9.8 )

=> W = 0 .

As the acceleration of the lift is 9.8 m/s^2 that is equal to acceleration due to gravity then this case is equal to the free fall ones ( a = g ) ,, Hence Apparent weight is = 0 .



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