A body of weight 80kgf is taken inside the surface of the earth. At what depth its weight will be 60kgf (Assuming density of earth to be uniform) [R = 6400 km]
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Calculate the new length of a 7.6 m abseiling rope when 4.8x10² J of elastic potential energy are stored in the stretched rope.
Give your answer correct to 3 significant figures. The spring constant of the rope is 9.0x10² N/m
Use the correct equation from the Physics Equation Sheet.
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