A body of weight w rest on a rough horizontal plane.The least horizontal force that can move the body along the plane is W ÷√3 .Then the limiting angle of friction for those two surface in contact is:
1)30°
2)45°
3)60°
4)None
Answers
Answered by
4
#BAL
Given :
Weight W rest on a rough horizontal plane.
Angle of friction = theta
We know that,
F = mg
mg = W
Angle of friction = Angle of repose
Since,
When a body is kept on an inclined plane inclined at an angle equal to angle of repose then it will be ready to move.
Therefore,
F = mg × sin theta
F = W sin theta
Hence,
W sin theta is the required answer
Answered by
6
Explanation:
I hope it helps you
please mark as brainlist
Attachments:
Similar questions