Question

a body on which a firce 5i^ +4j^ + 10k^ netwon acts is displaces from 2i^ +5j^ + 4k^ meter to 7i^+7j^ +8k^ meter. what is the kinetic energy gained by the body​

Answer 1

Answer:

Displacement = (7i^+7j^ +8k^) - (2i^ +5j^ + 4k^) = 5i^ + 2j^ + 4k^

Kinetic energy gained = Work done

                                       =  F . s

                                      = (5i^ +4j^ + 10k^). ( 5i^ + 2j^ + 4k^)

                                      = 25 + 8 + 40 = 73