Question

A body, oscillates with SHM according to use equations x = (5 cm) sin {(2π rad/s)t + π/4rad) At t = 1.5s calculate (a) displacement (b) speed and (c) acceleration ​

Answer 1

Answer:

hope you will do it yourself

Answer 2

Answer:

HERE ARE MY ANSWER,

T=2π = 2 π = 1s, t = 1.5s

ω ω

T=2π = 2 π = 1s, t = 1.5s

ω ω

(a)

(a)

displacement,

s=

(5.0)

cos

[2π×1.5+π/4]

s=(5.0)cos[2π×1.5+π/4]

=5.0

cos

(3π+π/4)=−5.0

cosπ/4

=5.0cos(3π+π/4)=-5.0cosπ/4

=-5.0xx0.707=-3.535m

(b)

(b) speed,

v= dxdt

v=dxdt

=−5.0×2π

sin

(2πt+π/4)

=-5.0×2πsin(2πt+π/4)

=−5.0×2π

sin

(2π×1.5+π/4)

=-5.0×2πsin(2π×1.5+π/4)

=5.0×2π×

sin

(

π

4. 22

)=5.0×2×7×0.707

=5.0×2π×sin(π4)=5.0×2×227×0.707

=22.22m S-¹

=22.22ms-1

A= dt

(c) dt

(c) Acceleration A=dvdt

=−5.0×4 π 2cos

(2πt+

π

4

)

=-5.0×4π2cos(2πt+π4)

=−5.0×4× ( 22)² ×× 0.707=139.56m

7

=-5.0×4×(227)2××0.707=139.56ms-2

I HOPE IT HELPS:>