Question

A body oscillates with simple harmonic motion according to the equation : X= (10 0cm) cos (27 t +16). At t= 1/6 s. What is the velocity of the motion ?​

Answer 1

Answer:

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>>A body oscillates with SHM according to

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A body oscillates with SHM according to the equation x=5.0cos(2πt+π). At time t=1.5s, its displacement, speed and acceleration respectively is:

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Solution

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Correct option is B)

Given,

x=5cos(2πt+π)

t=1.5sec

Displacement, x=5cos(2π×1.5+π)=5cos(4π)

x=5m. . . . . .(1)

Velocity, v=

dt

dx

v=−10πsin(2πt+π)

v=−10πsin(2π×1.5+π)

v=−10πsin(4π)

v=0m/s. . . . .(2)

Acceleration, a=

dt

dv

a=−20π

2

cos(2πt+π)

a=−20π

2

cos(2π×1.5+π)

a=−20π

2

cos(4π)

a=−20π

2

The correct option is B.