Question

A body placed on a rough inclined plane just begins to slide, when the slope of the plane is 1 in 4. Calculate the coefficient of friction.

Give me correct answer.....❤​

Answer 1

Given:

A body placed on a rough inclined plane just begins to slide, when the slope of the plane is 1 in 4.

To find:

Value of coefficient of friction ?

Calculation:

At equilibrium conditions, the component of weight down the inclined plane will be equal and opposite to the frictional force of the inclined plane.

$\therefore \: mg \sin( \theta) = \mu \bigg \{mg \cos( \theta) \bigg \}$

$\implies\: \sin( \theta) = \mu \bigg \{ \cos( \theta) \bigg \}$

$\implies\: \mu = \dfrac{ \sin( \theta) }{ \cos( \theta) }$

$\implies\: \mu = \tan( \theta)$

$\implies\: \mu = slope \: of \: incline$

$\implies\: \mu = \dfrac{1}{4}$

$\implies\: \mu = 0.25$

So, the coefficient of friction is 0.25 .

Answer 2

Explanation:

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