a body posses an initial velocity of 5ms to power -1 and moves with a uniform acceleration of 2ms raised to power -2.Calculate the distance moved by the body in 4 secs
Answers
Answer
Distance moved by the body in 4 s is 36 m
Given
Initial velocity of a body is 5 m/s
Uniform acceleration of the body is 2 m/s²
Time taken is 4 s
To Find
Distance moved by the body
Concept Used
As the acceleration is constant through out the motion , so we need to apply equation's of motion
Solution
Initial velocity , u = 5 m/s
Acceleration , a = 2 m/s²
Time , t = 4 s
Distance , s = ? m
Apply 2nd equation of motion ,
So , Distance moved by the body in 4 s is 36 m
Answer:
✡ Question ✡
✏ A body posses an initial velocity of 5ms to power -1 and moves with a uniform acceleration of 2ms raised to power -2.Calculate the distance moved by the body in 4 secs.
✡ Given ✡
➡Initial velocity of a body = 5 m/s
➡Uniform acceleration of the body=2 m/s²
➡Time taken is 4 s
✡ To Find ✡
➡Distance moved by the body
✡ Solution ✡
➡Initial velocity , u = 5 m/s
➡Acceleration , a = 2 m/s²
➡Time , t = 4 s
➡Distance , s = ? m
▶We have to apply 2nd equation of motion ,
=> s = (5)(4) + 1/2 (2)(4)²
=> s = 20+16
=> s = 36 ✔
Hence, Distance moved by the body in 4 s is 36 m.
Explanation: