Question

A body posses KE 3920 J and PE 5880 J at a point in its path. If its mass is 20 kg, what is the maximum height reached by it

Answer 1

Answer:

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Explanation:

$to \: find = \\ maximum \: height \: reached \: by \: body \: (h) \\ \\ given = \\ kinetic \: energy \: (K.E) = 3920 \: J \\ potential \: energy \: (P.E) = 5880 \: J \\ mass \: of \: body \: (m) = 20 \: kg \\ acceleration \: due \: to \: gravity \: (g) = 9.8 \: m/s {}^{2} \\ \\ so \: we \: know \: that \\ P.E = mgh \\ 5880 = 20 \times 9.8 \times h \\ 5880 = 196 \times h \\ \\ h = \frac{5880}{196} \\ \\ = 30.m \\ \\ h = 30.m$

$hence \: maximum \: height \: reached \\ by \: body \: with \: P.E \: as \: 5880 \: J \: and \: mass \: 20 \: kg \\ is \: \: 30.m$