Question

a body possesses an initial velocity of 5 m/s and moves with a uniform acceleration of 2 ms-2. calculate the distance moved by the body in 4s.​

Answer 1

Answer:

HOPE IT HELPS,36m is your answer

Explanation:

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Answer 2

Answer:

36 metres

Explanation:

Given:

Initial velocity = 5 m/s (u)

Acceleration = 2 m/s² (a)

Time = 4 seconds (t)

To find:

Distance travelled in 4 seconds (s)

Using the second equation of motion, which says:

$s=ut+\frac{1}{2} at^{2}$

Where:

s = distance

u = initial velocity

t = time

a = acceleration

Substituting the values, we get:

s = 5×4 + $\frac{1}{2}$ × 2 ×4²

s = 20 +16

s = 36 metres

The distance travelled by the body is equal to 36 metres