Question

a body possesses initial velocity of 5 metre per second and moves with uniform acceleration of 2 metre per second calculate the distance moved by the body in 4 second​

Answer 1

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▪A body possesses initial velocity of 5 metre per second and moves with uniform acceleration of 2 metre per second calculate the distance moved by the body in 4 second.

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Given :-

⟹ Initial velocity of body:-5 m/s

⟹ Acceleration of body =2m/s sq.

⟹Time taken =4 second.

To find :-

Distance travelled by body in 4 second

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Now, Solution :-

By using 2nd equations of motion

⟹

$s = ut + \frac{1}{2} at {}^{2} \\ \\ s = 5 \times 4 + \frac{1}{2} \times 2 \times 16 \\ s = 20 + 16 \\ \\ s = 36m$

...hope this answer helps you..

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Answer 2

Answer:

Distance = 36 m

Explanation:

Initial Velocity = 5m/s, Acceleration = 2m/s^2 and time = 4 sec

s = ut + 1/2 at^2 (Seconds Equation Of Motion)

s = 5(4) + 1/2 (2) (4)^2

s = 20 + 2/2 × 16

s = 20 + 1 × 16

s = 20 + 16

s = 36 m