A body possessing an initial velocity of 2m/s-¹
covers a distance of 24m during the 6th
second of its motion calculate the acceleration
of the body assuming it to be constant.
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Answer:
a=12ms²
Explanation:
s=ut+1/2at²
24m=2m/s×6sec+1/2×a×12
24m=12+1/2×12a
24m=12+12a/2
24m=6+12a
12a=24-6
12a=18
a=18/12
a=3/2ms²
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