Question

A body produces a sound at a distance of 660m. Considering the speed of sound in air to be 330m/s, find the time taken for the sound to reach the observer.​

Answer 1

Answer:

Speed of the sound is,

v=vλ

v=

λ

v

=

0.01

340

=34000Hz

Our audible range is 20 Hz 20 kHz. The obtained frequency is above this value. Since the given sound wave belongs to the ultrasonic range, it is not audible.

Answer 2

Answer:

Speed of the sound is,

v=vλ

v=

λ

v

=

0.01

340

=34000Hz

Our audible range is 20 Hz 20 kHz. The obtained frequency is above this value. Since the given sound wave belongs to the ultrasonic range, it is not audible.

Explanation:

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