Question

a body project up eard with speed 10m/s then what will be maximum heingt​

Answer 1

physics is not my subject

sorry to say

Answer 2

$\large \underline \bold{Given}$

$\: \: \:$$\sf{speed \: of \: body \: (u) = 10 \: m/s}$

$\large \underline \bold{To \: Find}$:-

$\: \: \: \:$$\sf{maximum \: height \: (H) = ?}$

$\large \underline \bold{Usable \: Formula}$:-

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$$\large\boxed{\sf\red{H = \dfrac{u^{2}Sin 2O}{2g}}}$

$\sf{here \: ,}$

$\: \: \: \: \: \:$$\sf{H = height}$

$\: \: \: \: \: \:$$\sf{u = speed}$

$\: \: \: \: \: \:$$\sf{O = angle}$

$\: \: \: \: \: \:$$\sf{g = 10 \: m/s^{2}}$

$\large \underline \bold{Solution}$:-

$\sf{On \: maximum \: height \: - \: O = 45}$°

$\sf{So \: ,}$

$\: \: \: \: \: \: \: \:$$\sf{H\displaystyle{max} = \dfrac{u^{2} Sin 90}{2g}}$

$\: \: \: \: \: \: \: \:$$\sf{H\displaystyle{max} =\dfrac{(10)^{2} (1)^{2}}{2(10)}}$

$\: \: \: \: \: \: \: \:$$\sf{H \displaystyle{max} = \dfrac{100\times 1}{20}}$

$\: \: \: \: \: \: \: \:$$\sf{H \displaystyle{max} = \dfrac{100}{20}}$

$\: \: \: \: \: \: \: \:$$\sf{H \displaystyle{max} = \dfrac{50}{10}}$

$\: \: \: \: \: \: \: \:$$\sf{H \displaystyle{max} = 5 \: m}$