Question

A body projected at 45° with a velocity of 20 m/s has a range of 10m. The decrease in range dueto air resistance is (g=10ms)1) 02) 10 m3) 20 m4) 30 m​

Answer 1

Answer:

correct answer is option d

Explanation:

find range first

R=u^2sin2a/g

=400/10

=40

now subtract this range by the given range

=40-10

=30

hope it helps