Question

A body projected at angle 30 to horizontal with a velocity 50 its time of flight g=10

Answer 1

You can use the formula for time of flight
t=[u^2 sin(2*theta)]/g

Therefore, t=125*sqrt(3)
Hope it helps :)

Answer 2

Given,. Angle= 30°
u= 50
g= 10


For time of flight for a projectile

$t = \frac{2u \sin(angle) }{g}$
$t = \frac{2 \times 50 \times \sin(30) }{10}$
$t = \: 5sec.$

Please mark it as the brainliest.