Question

A body projected horizontally with a velocity v from a height h has a range r with hat velocity a body is to be projected horizontally from a height h/2to have same range

Answer 1

Answer:

In y direction:

h=ut+

2

1

gt

2

So, t=

g

2h

In x direction

R=v×t

Now, In y direction

2

h

=uT+

2

1

gT

2

T=

g

h

So, comparing range:

v×

2h/g

=v

1

×

h/g

v

1

=v

2