a body projected up vertically up with a velocity 10m/s reaches a height of 20m. If it is projected with a velocity of 20m/s,then the maximum height reached by the body?......
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Using first case find angle of projection
H= usquare sinsquareQ / 2g
Hers u is 10 ms-1
H is 20m
Then calculate max. Height for the second case
Here u will be 20ms-1
Q is calculated in first case.
Hope you get your answer.
H= usquare sinsquareQ / 2g
Hers u is 10 ms-1
H is 20m
Then calculate max. Height for the second case
Here u will be 20ms-1
Q is calculated in first case.
Hope you get your answer.
Answered by
1
Using first case find angle of projection
H= usquare sinsquareQ / 2g
Hers u is 10 ms-1
H is 20m
Then calculate max. Height for the second case
Here u will be 20ms-1
Q is calculated in first case.
Hope you get your answer.
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