Question

A body projected up with a velocity 'u' reaches a
height 'h'. To reach double the height, it must be
projected up with a velocity of
​

Answer 1

Answer:

hope you will understand and it will help you

Answer 2

Answer:

$\sqrt{2} u$

Explanation:

v1 = u

v2 = ?

h1 = h

h2 = 2h

$(\frac{v1}{v2} )^{2}$ = $\frac{h1}{h2}$

$(v2)^{2}$ = $\frac{h2}{h1}$ × $(v1)^{2}$

$(v2)^{2}$  = $\frac{2h}{h}$ × $u^{2}$

$(v2)^{2}$ = 2$u^{2}$

v2 =  $\sqrt{2u^{2} }$

    = $\sqrt{2}$ u