a body projected upward is it same height from ground at t=equal to 1 seconds and t=9 second .find the maximum height attained by it. [g= 10 m/s]
Answers
Answered by
1
Answer:
Max height attained = 45 m
Explanation:
A body projected upward is it same height from ground at t=equal to 1 seconds and t=9 second .find the maximum height attained by it. [g= 10 m/s]
S = ut + (1/2)at²
a = -g = -10
S₁ = u*1 + (1/2)(-10)*1² = u - 5
S₉ = u*9 + (1/2)(-10)*9² = 9u - 405
u - 5 = 9u - 405
=> 8u = 400
=> u = 50
Speed at max height = 0
V² - u² = 2as
=> 0² - 50² = 2(-10)h
=> h = 125
Max height attained = 45 m
Similar questions