Question

A body projected vertically up from ground crosses a point P after 4 seconds and again after 6 seconds from starting. Maximum
height reached by that body above the ground is (g = 10 ms-2)
(A) 125 m
(B) 250 m
(C) 375 m
(D) 500 m​

Answer 1

Answer:

the answer of this question is (b)

Answer 2

Answer:

H=g/8(t1+t2)square

t1=4

t2=6

H=10/8(4+6)square

H=10/8(100)

H=125m

Explanation: