A body projected vertically up with a velocity of 20m returns to the ground with a velocity of 18m the maximum height attained by the body is
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Explanation:
Thrown with a velocity of 10 m/s, if it reaches a height of 20 m, the g at that place must be g = v^2/ 2h = 100/ 40 = 2.5m/s^2
Thrown with a velocity of 20 m/s,it will reach a height of
h = v^2/(2g) = 400/5= 80 m
Or simply ,
H2 = ( v2/v1)^2*H1=4 *20 = 80m
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