Question

A body projected vertically up
with a
velocity of
maximum height reached by the body
(g=10m/s²)
wards
50 m/s. find the​

Answer 1

Answer:Initial velocity of ball (u)=50m/s, acceleration of ball =−g,

final velocity at the highest point (v)=0

So applying the 3rd equation of motion we get:

v

2

=u

2

−2gh

max

​

⇒0=50

2

−2×10×h

max

​

⇒h

max

​

=

20

2500

​

v=u−gt

⇒0=50−10t

⇒t=

V

2

=50

2

−2g

2

125

​

⇒V

2

=2500−1250=1250

⇒V=

1250

​

=35.35m/

Explanation: