Question

a body projected vertically up with velocity u from the top of the tower reaches the foot of the tower with velocity 2u then height of the tower is​

Answer 1

Answer:

The height of the tower is 3u/20 meter

Explanation:

Concept: By using the third equation of motion can solve this problem

2as=v ^2−u^2

Where, v is the final velocity of the body projected , u is the initial velocity of the body, a is the acceleration of gravity and s is the height or distance travelled by body.

Given:

Initial velocity - u

final velocity - 2u

To find:

The height of the tower .

Step by step explanation

2as=v ^2 −u^2

2 x 10x h=( 2u)^2-(u)^2

h= 3u/20

So the height of the tower is 3u/20 meter .

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