Question

a body projected vertically upward with a velocity 19.6m/s reaches a height of 19.8m on earth. if it is projected vertically up with the same velocity on moon. then the maximum height reached by it is​

Answer 1

Answer:  118.8m

Explanation: we know,

acceleration due to gravity on the surface of the earth is 6 times of acceleration due to gravity on the surface of the moon.

  so, acceleration due to gravity on the surface of the moon, a =g/6

but g is not given, since, height attained by body on the surface of the earth is 19.8m

so, g = u²/2h = (19.6)²/2(19.8) = 9.7 m/s²

so, a = g/6 = 9.7/6 m/s²

now, initial velocity of the body, u = 19.6 m/s²

at maximum height, velocity of the body becomes zero

so, final velocity of the body, v = 0

now applying formula,

 v² = u² + 2as

or, 0 = (19.6)² + 2(-9.7/6)s

or, s = (19.6)²/2(9.7/6) = 118.8m

hence, height of the body reached from the surface of the moon is 118.8m

Answer 2

v^2 = u^2 - 2 gs

s = u^2/2 g = (19.6)^2 ÷ ( 2× [9.8÷6])

Since, g moon = g earth/6

s = 19.6 × 6 = 117.8 upon solving

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