Question

a body projected vertically upwards with a velocity u its velocity at 3/4th of its maximum height is​

Answer 1

Answer:

this is the answer

Explanation:

For a body projected up,

H  

max

​  

=  

2g

u  

2

 

​  

 

By equation

v  

2

=u  

2

−2gh

Putting, h=  

2

H  

max

​  

 

​  

=  

4g

u  

2

 

​  

 

v  

2

=u  

2

−2gv  

2

=u  

2

−2g  

4g

u  

2

 

​  

 

=u  

2

−  

2

u  

2

 

​  

 

v  

2

=  

2

u  

2

 

​  

 

v=  

2

​  

 

u

​

Answer 2

Answer:

here is ur answer

plz look at above pic.

hope this will helps u...be happy.....

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