Question

A body released from a great height falls freely towards earth. Another body is released from the same height exactly one second later. The separation between the two bodies two seconds after the release of the second body is

Answer 1

Explanation:

distance of first body after 3 sec. = 1/2gt2 =45

distance of second body after 2 sec. = 20

separation = 45-20 = 25

Answer 2

Answer:

24.5m

Explanation:

     case 1 : A body is released from a height  and falls freely towards the        earth.  

time taken = 2 s

so,

    S= ut+1/2 g t^2

      = (0)(2) + 1/2 (9.8) (2)^2

      = 0 + 19.6=19.6 m ---------------------------(1)

case 2 : Another body is released from the same height exactly one second later.

        s= ut+1/2 g t^2

       s= 0 + 1/2 (9.8) ( 4-1) ^ 2

       s= 1/2 (9.8)(3)^2

       s= 44.1 m---------------------------(2)

(2)-(1)------>   44.1-19.6=24.5 m