Question

A body released from a height falls freely towards earth on the body is released from the same point exactly one second later the separation between them two seconds after the release of the second body is

Answer 1

Displacement of the first body after 3 seconds= S = ut + ½ g t^2  = 44.1m/s

Displacement of the first body after 2 seconds= S = ut + ut + ½ g t^2  = 19.6m/s

The separation between them=44.5 - 19.6 = 24.5m/s

Answer 2

use the formula s=ut+1/2at-square