Question

A body released from a height falls freely towards the earth.another body is released from the same height a sec later.the the separation between the two bodies after two seconds after the release of the second body

Answer 1

Answer:

25m

Explanation:

for 1st body:

the time will be 3sec while for 2nd body it is 2sec only as it is released a second after the first body.

for 1st body,

h=1/2gt^2

1/2*9.8*(3)^2=45m

for second body,

=1/2*9.8*(4)^2=20m

therefore seperation =45-20=25m(approximately

Answer 2

Answer:

$(d) \: 24.5m$

Explanation:

$time \: for \: {1}^{st} \: ball = 2 \: seconds$

$time \: for \: {2}^{nd} \: ball = 2 + 1 = 3 \: seconds$

$S_{1} = \frac{1}{2} g( {2}^{2} ) \: and \: S_{2} = \frac{1}{2} g( {3}^{2} )$

$S_{2} - S_{1} = g / 2(9 - 4) = 4.9 \times 5 = 24.5m$

$hence \: \: verified$