Question

A body released from a height of 1 metre what time it will take to reach the surface of the earth

Answer 1

given acceleration of Earth,
$g = 9.8m \div {s}^{2}$
using formula,
$s = (1 \div 2) \times g \times {t}^{2}$
the time taken will be,
$\sqrt{1 \times 2 \div 9.8}$
or,
$t = 0.144s$