Question

A body released from height h takes time t to reach the ground After time t/2 its height from the ground is​

Answer 1

Answer:

Total Height=h

Total time taken=t

Initial velocity, u=0

Therefore using,

h=ut+(1/2)gt²

h=(1/2) gt² ………(1)

Now, let at time T=t/2

Height fallen be h'

Therefore,

h'=(1/2)gT²

h'=(1/2)g(t²/4)

h'=h/4 ….. Using equation (1)

Now, height from the ground after time t/2 = H

H=h-h'

H=h-(h/4)

H=3h/4

H=0.75h

Which is our required answer…