Question

a body revolve in a Con stant speed v in circular path of radius r. the magnitude of itsaverage acceleration during motiin between two ooints in diameteically opposite direction

Answer 1

T=2πr/v 

T/2=πr/v = t 

a=v-(-v)/t 

=2v/t 

=2v^2/πr

Answer 2

HeÿA MäTè ❤❤

$T = \frac{2\pi r}{v}$

$\frac{T}{2} = \pi \frac{r}{v} = t$

$a = v - \frac{( - v)}{t}$

$= \frac{2v}{t}$

$= \frac{2 {v}^{2} }{\pi \: r}$

HöPe ïT hèLps u ☺