a body Rises vertically up to a height of 125 m in 5 second and then comes back at the point of projection find the total distance travelled ; the displacement ;the average speed and the average velocity of the body
Answers
Hey Dear,
◆ Answer -
Total distance = 250 m
Displacement = 0 m
Average speed = 25 m/s
Average velocity = 0 m/s
● Explanation -
Time taken by the body to come back ground -
s = ut + 1/2 gt^2
125 = 0 × t + 1/2 × 10 × t^2
t^2 = 125 / 5
t = 5 s
Total time taken by the hody to return at point of projection -
Total time = 5 + 5
Total time = 10 s
Total distance travelled will be double the height.
Total distance = 2h
Total distance = 2 × 125
Total distance = 250 m
As the body comes back at the point of projection, displacement is zero.
Displacement = 0 m
Average speed is calculated as -
Average speed = distance / time
Average speed = 250 / 10
Average speed = 25 m/s
Average velocity is calculated as -
Average velocity = displacement / time
Average velocity = 0 / 10
Average velocity = 0 m/s
Thanks for asking...