Question

A body rises vertically upwards to a height of 100 m in 5 seconds, then comes back to the same position after another 5 s. Find the distance travelled , displacement, average speed and average velocity of the body. (Ans. Distance = 200 m, Displacement = 0, Average speed = 20m/s, Average velocity = 0)

Answer 1

Distance is the actual path covered by an object

The object goes up by 100m and comes down by 100m

Total distance=200m

Displacement is the shortest distance between the initial and final position

As the initial and final position of the object is same displacement is zero

Average speed is the ratio of total distance(200m) travelled by an object and

total time(10sec)

Average speed=200/10=20m/s

Average velocity

=total displacement/total time

=0/10

=0

I hope this helps ( ╹▽╹ )

Answer 2

Explanation:

hope it's help full for you(´∩｡• ᵕ •｡∩`)