Question

A body rolling on a horizontal surface. Derive an equation for its kinetic energy

Answer 1

kinetic energy =1/2*mass *velocity squared

Answer 2

Explanation:

ANSWER

Total Rolling kinetic energy=Translational K.E+Rotational K.E

=

2

1

MV

2

+

2

1

Iω

2

But ω=

R

V

K.E=

2

1

MV

2

+

2

1

I(

R

V

)

2

=

2

1

MV

2

+

2

1

I(

R

2

V

2

)

For solid sphere I=

5

2

MR

2

K.E=

2

1

MV

2

+

2

1

×

5

2

MR

2

×(

R

2

V

2

)

=

2

1

MV

2

+

5

1

MV

2

=

10

7

MV

2