Question

A body slides down a smooth 30 degree incline 9.8m long. The time of descent is:​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Time\:taken=2\:sec}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Angle \: of \: elevation = 30 \degree \\ \\ \tt: \implies Length(s) = 9.8 \: m \: \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Time \: of \: descent(t) = ?$

• According to given question :

$\tt \circ \: Downward \: acceleration = g \: sin \theta \: m/{s}^{2} \\ \\ \tt \circ \:Length = 9.8 \: m \\ \\ \tt \circ \: Value \: of \: g = 9.8 \: m/{s}^{2} \\ \\ \tt \circ \: Initial \: velocity = 0 \: m/s \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies s = ut + \frac{1}{2} a {t}^{2} \\ \\ \tt: \implies 9.8 = 0 \times t +\frac{1}{2} gsin \: \theta \times t^{2} \\ \\ \tt: \implies 9.8 = 9.8 \times \frac{1}{2} sin \: 30 \degree \times t^{2} \\ \\ \tt: \implies \frac{9.8}{9.8} = \frac{1}{4} \times t^{2} \\ \\ \tt: \implies 4 = t^{2} \\ \\ \green{\tt: \implies t = 2 \: sec}$

Answer 2

$\tt{\huge {\pink {Hello!!! }}}$

Question :

A body slides down a smooth 30 degree incline 9.8m long. The time of descent is :

Solution :

$\tt{\orange {Step-By-Step-Explaination \: :- }}$

$\tt{ \purple{ \leadsto{a \: = g \sin( \phi) - \dfrac{ \nu \: n \: \cos( \phi) }{ma} }}}$

Solving...

$\tt{ \red{ \leadsto{a \: = 3.62 \: m. {s}^{ - 2} }}}$

$\tt{ \blue{ \mapsto{t \: = \: {( \dfrac{2s}{a}) }^{ \frac{1}{2} } }}}$

Solving...

$\tt{ \green { \leadsto{t \: = 2 \: sec.}}}$