Question

A body slides over an inclined plane forming an angle of 45° with the horizontal. The distance x travelled by the body in time t is described by the equaiton x-kt^2,where k=1.732. The coefficient of friction between the body and the plane has a value

please help me

no spam!!​

Answer 1

Answer:

A body slides over an inclined plane of forming an angle of 45∘ with the horizontal. The distance x travelled by the body in time t is described by the equation x=kt2 where k=1.732.

Answer 2

Answer:

given,x=kt^2. k=1.732

Explanation:

dx/dt=2kt -----dx^2/dt^2=a=2k=2×1.732=3.464

a.=gsintheta-ucostheta=3.464 g/√2-u√2=3.464.

u=0.06