Question

a body slides with an acceleration of 3.2 m/s^2 down an inclined plane with the slope of 30 degree . find the coefficient of friction

Answer 1

The net acceleration by the sliding object is given by
A = gmsin@ - ugmcos@/mm
gm comes out as they are common
3.2 = 5-5√3u
-1.8 = -8.6u
0.20.. = u hence this has to be the coefficient of fiction

Answer 2

Answer: Coefficient of friction (COF) is a dimensionless variety this is described as the ratio among friction pressure and regular pressure Materials with COF smaller than 0.1 are taken into consideration lubricous substances. COF relies upon on the character of the substances and floor roughness.

⇒mgsinθ-f = ma

⇒mgsinθ-μmgcosθ= 3.2$m/s^{2}$

⇒3.2$m/s^{2}$ = 5-5$\sqrt{3}$

⇒-1.8=8.6μ

⇒μ=0.20

This is the cofficient of friction.

kinds of friction coefficient :- Two kinds of friction coefficient are distinguished: the static friction coefficient and the kinetic friction coefficient. The former is from time to time known as the beginning friction coefficient, and the latter is from time to time known as the dynamic or sliding friction coefficient.

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