Question

A body slides with an initial velocity of 0.5m/sec. Due to friction, its
velocity decreases at the rate of 0.05 m/sec2 .How much time will be
required for the body to stop?

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity of body, u = 0.5 m/s

Final velocity of body, v = 0

Acceleration by body, a = 0.05 m/s²

To Calculate,

Time taken by body, t = ??

According to the 1st equation of motion,

We know that,

v = u + at

Putting all the values, we get

v = u + at

0 = 0.5 + 0.05 × t

0.5 = 0.05t

0.5/0.05 = t

t = 10 seconds

Hence, the time taken by body is 10 seconds.

Answer 2

★ Given :

• Initial velocity (u) = 0.5 m/s
• Final velocity (v) = 0 m/s
• Acceleration (a) = -0.05 m/s²

★ To Find :

We have to find the time taken by the body

★ Explanation :

As, we have to find the time taken by the body. So, to find the time taken by the body we will use the first equation of motion.

A.T.Q

$\large{\star{\underline{\boxed{\sf{v = u + at}}}}}$

$\sf{\dashrightarrow 0 = 0.5 + (-0.05) \times t } \\ \\ \sf{\dashrightarrow \cancel{-} 0.5 = \cancel{-} 0.05t} \\ \\ \sf{\dashrightarrow 0.5 = 0.05t} \\ \\ \sf{\dashrightarrow t = \dfrac{0.5}{0.05}} \\ \\ \sf{\dashrightarrow t = 10} \\ \\ \large{\star{\underline{\boxed{\sf{t = 10 \: s}}}}}$

$\rule{400}{4}$