Question

a body sliding on a rough horizontal plane surface moves with a retardation of 6m/s2. what is the coefficient of kinetic friction between the two surface in contact​

Answer 1

Answer:

answer-0.2

Explanation:

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Answer 2

Given: A body sliding on a rough horizontal plane surface moves with a retardation of 6ms⁻².

To find: The coefficient of kinetic friction between the two surfaces in contact.

Solution:

• The forces acting between two surfaces in relative motion is called kinetic frictional force.
• When a body is in uniform motion the force of kinetic friction is,

        $f_{k} = \mu _{k} R$

• Here, $\mu _{k}$ is the coefficient of kinetic friction and R is the normal reaction or the reaction force.
• But the normal reaction is equal to the product of the mass of the body and the acceleration due to gravity acting on it.

       $R = mg$

• Hence,

        $f_{k} = \mu _{k} mg$

• Acceleration of a body can be given by the formula,

        $acceleration = \frac{force}{mass}$

• So, the kinetic frictional force divided by the mass of the body can be replaced by acceleration

        $a = \mu_{k} g$

        $6ms^{-2} = \mu_{k} (10ms^-2)$

        $\mu_{k} = 0.6$

Therefore, the coefficient of kinetic friction between the two surfaces in contact is 0.6