A body sliding on a smooth inclined plane requires 4 seconds to reach the bottom starting from rest at the top. How much time does it take to cover one-fourth distance starting from rest at the top ?
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Answer:
Suppose length of plane is L. When block descends the plane, rise in kinetic energy = fall in potential energy =mgLsinθi
Work done by friction =μ×(reaction)×distance 0+μ(mgcosθ)×(L/2)
=μ(mgcosθ)×(L/2)
Now, work done= change in KE
mgLsinθ=μ(mgcosθ)×(L/2)
⇒tanθ=μ/2
∴μ=2tanθ.
Explanation:
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