Question

A body sliding on ice with a velocity 8m/s comes to rest after travelling 40m.find the coefficient of friction g=9.8m/s2.....
answer should be 0.0816

Answer 1

v² = u² + 2as

0 = 8² - 2a(40) (S= distance)

a= 0.8

a = K.g = 0.8 (g is acceleration due to gravity, value = 10m/s²)

K = 0.08

Be brainly ;)

Answer 2

Answer:

Explanation:

Hope this helps!