Physics, asked by ramuludandu, 9 months ago


A body slipping on a rough horizontal plane moves with a deceleration of 4 ms. The coefficient of
kinetic friction between the block and the plane is (g = 10 ms?)

Answers

Answered by VedankMishra
7

Answer:

ANSWER

Let the mass be m.

Then on the horizontal surface, normal force is N=mg.

Hence friction is f =

=μN=μmg</p><p></p><p></p><p> \\

Hence deceleration is a

 \frac{f}{m} =μg</p><p></p><p></p><p> \\

</p><p>⟹μg=4⟹10μ=4</p><p></p><p></p><p> \\

⟹μ=0.4</p><p></p><p> \\

Answered by TheValkyrie
5

Answer:

\bigstar{\bold{\mu _k = 0.4}}

Explanation:

\Large{\underline{\underline{\bf{Given:}}}}

  • Deceleration of the body (a)= 4 m/s²
  • Acceleration due to gravity (g) = 10 m/s²

\Large{\underline{\underline{\bf{To\:Find:}}}}

  • Coefficient of kinetic friction (\mu _k)

\Large{\underline{\underline{\bf{Solution:}}}}

→ Let mass of the body be m

→ The coefficient of kinetic friction is given by the equation,

   F_k = \mu _k \: F_n-----(1)

→ Here F_k is the force of kinetic friction and F_n is the weight of the body.

F_k is given by mass × acceleration

→ Substituting the datas we get,

  F_k=m\times 4

  F_k=4\:m----(2)

F_n is given by mass × acceleration due to gravity

→ Substituting the datas,

   F_n=m\times 10

  F_n=10\:m-----(3)

→ Substitute equation 2 and 3 in equation 1

   4\:m=\mu _k\times 10\:m

→ Cancelling m on both sides

  4=\mu _k\:10

 \mu _ k =4/10

 \mu _k = 0.4

→ Hence the coefficient of kinetic friction is 0.4

  \boxed{\bold{\mu _k = 0.4}}

\Large{\underline{\underline{\bf{Notes:}}}}

The three types of friction are :

→ Static friction: The opposing force that comes into play when one body     tends to move on surface of another, but the actual motion has yet not started is called static friction

 F_s=\mu _s\:mg

→ Limiting friction : The maximum opposite force that comes into play when the body is just at the verge of moving over the surface of another body.

 F_l=F_s(max)

→Kinetic friction: It is the opposite force that comes into play when one body is actually moving over surface of another body

F_k=\mu _k \: mg

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