Question

A body slipping on a rough horizontal plane moves with a deceleration of 4.0 m/s². What is the coefficient of kinetic friction between the block and the plane ?Concept of Physics - 1 , HC VERMA , Chapter 6:Friction "

Answer 1

Solution :
The frictional force=F=ma
where m is mass and a= deceleration of the body =4.0 m/s2
so f=4m N
Normal force= Weight of the body=mg
So coefficient of Kinetic friction = 4m/mg
=4/g
=4/10
=0.4
 Hence the coefficient of kinetic friction between the block and the plane is 0.4.

Answer 2

HEY!!

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Let m be the mass of that body

R − mg = 0

Where R is the normal reaction force and g is the acceleration due to gravity

R = mg       - - - - - -----(1)

ma − μkR = 0

(where μk is the coefficient of kinetic friction and a is deceleration)

ma = μkR

From Equation (1),
ma =  μkmg

a = μkg

4 = μkg

μk=4g=410=0.4

⚫Hence, the coefficient of the kinetic friction between the block and the plane is 0.4.